huagongshe.com
HRID23474

反应详情

EQUATION

反应方程式

HRID 23474 的结构方程式

REACTANTS

反应物

4
结构：c1ccncc1
HCID1049

Pyridine

C5H5N

结构：ClC(Cl)(Cl)Cl
HCID5943

Carbon tetrachloride

CCl4

结构：Cc1ccc(S(=O)(=O)Br)cc1
HCID10130885

tosyl bromide

C7H7BrO2S

结构：CC(C)(C)OC(=O)n1ccc2cc(S)c(C(C)(C)C)cc21
HCID54456211

未命名化合物

PRODUCTS

生成物

1
结构：Cc1ccc(S(=O)(=O)Sc2cc3ccn(C(=O)OC(C)(C)C)c3cc2C(C)(C)C)cc1
HCID54161612

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOC(C)=O
溶剂HCID8857

Ethyl acetate

C4H8O2

PROCEDURE

实验过程

The title compound was prepared according to General Method 15 using 6-tert-butyl-5-mercapto-indole-1-carboxylic acid tert-butyl ester (prepared in Example FF), pyridine, tosyl bromide, carbon tetrachloride, and EtOAc.