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HRID23497

反应详情

EQUATION

反应方程式

HRID 23497 的结构方程式

REACTANTS

反应物

4
结构：c1ccncc1
HCID1049

Pyridine

C5H5N

结构：ClC(Cl)(Cl)Cl
HCID5943

Carbon tetrachloride

CCl4

结构：Cc1ccc(S(=O)(=O)Br)cc1
HCID10130885

tosyl bromide

C7H7BrO2S

结构：CCOC(=O)c1cc2cc(S)c(C(C)(C)C)cc2[nH]1
HCID69736019

未命名化合物

PRODUCTS

生成物

1
结构：CCOC(=O)c1cc2cc(SS(=O)(=O)c3ccc(C)cc3)c(C(C)(C)C)cc2[nH]1
HCID53677415

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOC(C)=O
溶剂HCID8857

Ethyl acetate

C4H8O2

PROCEDURE

实验过程

The title compound was prepared according to General Method 15 using (6-tert-Butyl-5-mercapto-1H-indole-2-carboxylic acid ethyl ester (prepared in Example AAA), pyridine, tosyl bromide, carbon tetrachloride, and EtOAc.