Tetrabutylammonium Fluoride → HCID 71293490, compound
Reaction equation
[CH3:1][O:2][C:3]([C:5]1[CH:10]([C:11]2[CH:16]=[CH:15][C:14]([C:17]#[N:18])=[CH:13][CH:12]=2)[N:9]2[C:19](=[O:39])[N:20]([CH2:22][CH2:23][CH2:24][S:25]([CH2:28][CH2:29][CH2:30][O:31][Si](C(C)(C)C)(C)C)(=[O:27])=[O:26])[N:21]=[C:8]2[N:7]([C:40]2[CH:45]=[CH:44][CH:43]=[C:42]([C:46]([F:49])([F:48])[F:47])[CH:41]=2)[C:6]=1[CH3:50])=[O:4].CCCC[N+](CCCC)(CCCC)CCCC.[F-]>C1COCC1>[CH3:1][O:2][C:3]([C:5]1[CH:10]([C:11]2[CH:12]=[CH:13][C:14]([C:17]#[N:18])=[CH:15][CH:16]=2)[N:9]2[C:19](=[O:39])[N:20]([CH2:22][CH2:23][CH2:24][S:25]([CH2:28][CH2:29][CH2:30][OH:31])(=[O:26])=[O:27])[N:21]=[C:8]2[N:7]([C:40]2[CH:45]=[CH:44][CH:43]=[C:42]([C:46]([F:48])([F:47])[F:49])[CH:41]=2)[C:6]=1[CH3:50])=[O:4]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Intermediate 21 (282 mg, 0.38 mmol) was dissolved in THF (3 mL), and then a solution of 1 M TBAF in THF (760 μl, 0.76 mmol) was added. The reaction mixture was stirred at RT for 4 hours and then partitioned between EtOAc and water. The organic layer was separated, and the aqueous layer further extracted with EtOAc. The combined organic layers were washed with brine, dried (Na2SO4) and evaporated in vacuo. The resulting residue was purified by silica gel chromatography eluting with a gradient of 0-2% methanol in EtOAc to afford the title compound (89 mg).
Workup
- custompartitioned between EtOAc and water
- customThe organic layer was separated
- extractionthe aqueous layer further extracted with EtOAc
- washThe combined organic layers were washed with brine
- dry with materialdried (Na2SO4)
- customevaporated in vacuo
- customThe resulting residue was purified by silica gel chromatography
- washeluting with a gradient of 0-2% methanol in EtOAc
Sources & evidence
- ORD record
- ord-7f85816bdcca4684a1e958494d937384
- Source dataset
- uspto-grants-2014_04
- Patent number
- US08691826B2
Reaction notes
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