Sulfuric Acid → Fuming sulfuric acid
Reaction equation
[S:1](=[O:5])(=[O:4])([OH:3])[OH:2].[S:6](=[O:9])(=[O:8])=[O:7]>>[OH:4][S:1]([OH:5])(=[O:3])=[O:2].[O:7]=[S:6](=[O:9])=[O:8]Participants
Procedure
It can be seen that these figures represent a 99.7% conversion of sulfur dioxide to sulfur trioxide and, therefore, a sulfur trioxide:sulfur dioxide ratio in the effluent of about 340:1. Cooling this effluent to 40° C. will condense 88% of the sulfur trioxide without condensing the sulfur dioxide to produce a liquid of pure sulfur trioxide, and a remaining gas mixture of 60.80% oxygen, 28.95% sulfur trioxide, 9.56% nitrogen, and 0.69% sulfur dioxide. Such remaining gas mixture can be absorbed in sulfuric acid in a conventional fashion and passed through a demister to produce a stack gas of 85.5% oxygen, 13.46% nitrogen and 0.97% sulfur dioxide. The sulfuric acid produced could be mixed with a portion of the liquid sulfur trioxide to produce one or more oleum products of varying strengths.
Sources & evidence
- ORD record
- ord-d92eab794606430bba3f03de7045cf21
- Source dataset
- uspto-grants-1987_02
- Patent number
- US04643887
Reaction notes
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