HRID2369845

反应详情

EQUATION

反应方程式

HRID 2369845 的结构方程式

PROCEDURE

实验过程

The title compound was prepared from compound 11 (130 mg, 0.215 mmol) following the procedure described in Example 5 for the synthesis of compound 9. Compound 12 (68 mg, 56% yield) was obtained.