Lithium Hydroxide → 2-Indancarboxylic Acid
Reaction equation
[C:1]([C:6]1(C(OCC)=O)[CH2:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[CH2:7]1)([O:3]CC)=[O:2].[OH-].[Li+]>C(O)C>[C:1]([CH:6]1[CH2:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[CH2:7]1)([OH:3])=[O:2]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Dissolve 2,2-dicarboethoxy-indan (5.67 g, 21.7 mmol) in ethanol (150 mL). Add 1N lithium hydroxide (50 mL) and stir overnight at room temperature. Reflux for 1 hour and concentrate the solution in vacuo. Partition betweenethyl acetate and 6N hydrochloric acid. Separate the organic phase and washwith brine. Dry (MgSO4) and evaporate the solvent in vacuo to give an off-white solid. Distill (120°-160° C. @0.2-0.5 mmHg) to give 2-carboxy-indan (2.5 g, 71%).
Workup
- temperatureReflux for 1 hour
- concentrationconcentrate the solution in vacuo
- customPartition betweenethyl acetate and 6N hydrochloric acid
- customSeparate the organic phase
- dry with materialDry (MgSO4)
- customevaporate the solvent in vacuo
- customto give an off-white solid
- distillationDistill (120°-160° C. @0.2-0.5 mmHg)
Sources & evidence
- ORD record
- ord-38962027947f4a4281b72db6231a2a57
- Source dataset
- uspto-grants-1996_02
- Patent number
- US05491142
Reaction notes
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