Stearic Acid → Monostearin
Reaction equation
[CH2:1]1[O:3][CH:2]1[CH2:4][OH:5].[C:6]([OH:25])(=[O:24])[CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH3:23]>>[CH3:23][CH2:22][CH2:21][CH2:20][CH2:19][CH2:18][CH2:17][CH2:16][CH2:15][CH2:14][CH2:13][CH2:12][CH2:11][CH2:10][CH2:9][CH2:8][CH2:7][C:6]([O:25][CH2:1][CH:2]([OH:3])[CH2:4][OH:5])=[O:24]Participants
3
Reactant 2
Product 1
Procedure
The experiment was carried out under the same conditions as in Example 3 but using a molar ratio of glycidol:stearic acid of 1.3:1. After 3 hours the amount of glycidol equivalent to the stearic acid had reacted and the mixture was cooled and worked up in a manner analogous to Example 1. There were obtained 116 grams of monostearin (80.9% yield) with the following properties:
Workup
- temperaturethe mixture was cooled
Sources & evidence
- ORD record
- ord-7c1e65256c354ced9997f17998acba73
- Source dataset
- uspto-grants-1977_05
- Patent number
- US04025540
Reaction notes
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