HRID2418587

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：CC(C)(C)OC(=O)N1CCC[C@H]1C(=O)N[C@H](Cc1ccccc1)C(=O)N[C@@H](Cc1ccccc1)C(=O)NN

HCID131713729

未命名化合物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@H](N)Cc1ccccc1)C(N)=O.Cl

HCID131713768

未命名化合物

PRODUCTS

生成物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@@H](Cc1ccccc1)NC(=O)[C@H](Cc1ccccc1)NC(=O)[C@@H](Cc1ccccc1)NC(=O)[C@@H]1CCCN1C(=O)OC(C)(C)C)C(N)=O

HCID131713770

未命名化合物

收率 91%

PROCEDURE

实验过程

Condensation of BocPro-DPhe-PheNHNH2 (2.09 g.) and HDPhe-Leu-MetNH2 hydrochloride salt (1.78 g.) by the acyl azide method (Yajima et al., Chem. Pharm. Bull., vol. 19, p. 1900, 1971) gave BocPro-DPhe-Phe-DPhe-Leu-MetNH2 in 91% yield. De-t-butoxycarbonylation of BocPro-DPhe-Phe-DPhe-Leu-MetNH2 (2.32 g.) using hydrogen chloride in ethyl acetate gave HPro-DPhe-Phe-DPhe-Leu-MetNH2, which was isolated as the amorphous white solid phosphate (1:1) salt dihydrate in 44% yield.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-2c061801ee6d4c23be4bcc4d0dc1cd9e
来源数据集: uspto-grants-1984_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04472305
来源说明: uspto-grants-1984_09

反应 SMILES

[N:1]1([C:32]([O:34][C:35]([CH3:38])([CH3:37])[CH3:36])=[O:33])[CH2:31][CH2:30][CH2:29][C@H:2]1[C:3]([NH:5][C@@H:6]([C:14]([NH:16][C@H:17]([C:25]([NH:27]N)=[O:26])[CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=1)=[O:15])[CH2:7][C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1)=[O:4].N[C@@H:40]([C:48]([NH:50][C@H:51]([C:56]([NH:58][C@H:59]([C:64]([NH2:66])=[O:65])[CH2:60][CH2:61][S:62][CH3:63])=[O:57])[CH2:52][CH:53]([CH3:55])[CH3:54])=[O:49])[CH2:41][C:42]1[CH:47]=[CH:46][CH:45]=[CH:44][CH:43]=1.Cl>>[N:1]1([C:32]([O:34][C:35]([CH3:38])([CH3:37])[CH3:36])=[O:33])[CH2:31][CH2:30][CH2:29][C@H:2]1[C:3]([NH:5][C@@H:6]([C:14]([NH:16][C@H:17]([C:25]([NH:27][C@@H:40]([C:48]([NH:50][C@H:51]([C:56]([NH:58][C@H:59]([C:64]([NH2:66])=[O:65])[CH2:60][CH2:61][S:62][CH3:63])=[O:57])[CH2:52][CH:53]([CH3:54])[CH3:55])=[O:49])[CH2:41][C:42]1[CH:43]=[CH:44][CH:45]=[CH:46][CH:47]=1)=[O:26])[CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=1)=[O:15])[CH2:7][C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1)=[O:4]