HRID2418615

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID6422

未命名化合物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)CNC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@@H]1CCCN1C(=O)OC(C)(C)C)C(N)=O

HCID131713803

未命名化合物

PRODUCTS

生成物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)CNC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@@H]1CCCCN1)C(N)=O

HCID131713805

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID12230

Ethyl methyl sulfide

C3H8S

溶剂HCID33645

Ethane-1,1-dithiol

C2H6S2

PROCEDURE

实验过程

Condensation of BocPro-DTrp-GlyOH (1.00 g.) and HDTrp-Leu-MetNH2 trifluoroacetate salt (1.10 g.) using dicyclohexylcarbodiimide and N-hydroxysuccinimide gave BocPro-DTrp-Gly-DTrp-Leu-MetNH2 in 36% yield. De-t-butoxycarbonylation of BocPro-DTrp-Gly-DTrp-Leu-MetNH2 (0.68 g.) using trifluoroacetic acid in methyl ethyl sulfide and ethanedithiol gave HPro-DTrp-Gly-DTrp-Leu-MetNH2, which was isolated as the amorphous white solid phosphate (2:3) salt in 59% yield.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-0d05d463cff64ad182933ec8c9a54182
来源数据集: uspto-grants-1984_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04472305
来源说明: uspto-grants-1984_09

反应 SMILES

[N:1]1([C:57](OC(C)(C)C)=O)[CH2:56][CH2:55][CH2:54][C@H:2]1[C:3]([NH:5][C@@H:6]([C:17]([NH:19][CH2:20][C:21]([NH:23][C@@H:24]([C:35]([NH:37][C@H:38]([C:43]([NH:45][C@H:46]([C:51]([NH2:53])=[O:52])[CH2:47][CH2:48][S:49][CH3:50])=[O:44])[CH2:39][CH:40]([CH3:42])[CH3:41])=[O:36])[CH2:25][C:26]1[C:34]2[C:29](=[CH:30][CH:31]=[CH:32][CH:33]=2)[NH:28][CH:27]=1)=[O:22])=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4].FC(F)(F)C(O)=O>C(SC)C.C(S)(S)C>[NH:1]1[CH2:57][CH2:56][CH2:55][CH2:54][C@H:2]1[C:3]([NH:5][C@@H:6]([C:17]([NH:19][CH2:20][C:21]([NH:23][C@@H:24]([C:35]([NH:37][C@H:38]([C:43]([NH:45][C@H:46]([C:51]([NH2:53])=[O:52])[CH2:47][CH2:48][S:49][CH3:50])=[O:44])[CH2:39][CH:40]([CH3:42])[CH3:41])=[O:36])[CH2:25][C:26]1[C:34]2[C:29](=[CH:30][CH:31]=[CH:32][CH:33]=2)[NH:28][CH:27]=1)=[O:22])=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4]