HRID2418629

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID6422

未命名化合物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@H](Cc1ccccc1)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)N(C)C(=O)[C@@H]1CCCN1C(=O)OC(C)(C)C)C(N)=O

HCID131713821

未命名化合物

PRODUCTS

生成物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@H](Cc1ccccc1)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)N(C)C(=O)[C@@H]1CCCCN1)C(N)=O

HCID131713823

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID12230

Ethyl methyl sulfide

C3H8S

溶剂HCID33645

Ethane-1,1-dithiol

C2H6S2

PROCEDURE

实验过程

Condensation of BocPro-MeDTrp-PheOH (3.68 g.) and HDTrp-Leu-MetNH2 acetate salt (part B of Example 17, 3.32 g.) using dicyclohexylcarbodiimide and N-hydroxysuccinimide gave BocPro-MeDTrp-Phe-DTrp-Leu-MetNH2 in 20% yield. De-t-butoxycarbonylation of BocPro-MeDTrp-Phe-DTrp-Leu-MetNH2 (1.00 g.) using trifluoroacetic acid in methyl ethyl sulfide and ethanedithiol gave HPro-MeDTrp-Phe-DTrp-Leu-MetNH2, which was isolated as the amorphous white solid phosphate salt monohydrate in 67% yield.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-f32eabaf647d48afafc24328db4ff84b
来源数据集: uspto-grants-1984_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04472305
来源说明: uspto-grants-1984_09

反应 SMILES

[N:1]1([C:65](OC(C)(C)C)=O)[CH2:64][CH2:63][CH2:62][C@H:2]1[C:3]([N:5]([CH3:61])[C@@H:6]([C:17]([NH:19][C@H:20]([C:28]([NH:30][C@@H:31]([C:42]([NH:44][C@H:45]([C:50]([NH:52][C@H:53]([C:58]([NH2:60])=[O:59])[CH2:54][CH2:55][S:56][CH3:57])=[O:51])[CH2:46][CH:47]([CH3:49])[CH3:48])=[O:43])[CH2:32][C:33]1[C:41]2[C:36](=[CH:37][CH:38]=[CH:39][CH:40]=2)[NH:35][CH:34]=1)=[O:29])[CH2:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1)=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4].FC(F)(F)C(O)=O>C(SC)C.C(S)(S)C>[NH:1]1[CH2:65][CH2:64][CH2:63][CH2:62][C@H:2]1[C:3]([N:5]([CH3:61])[C@@H:6]([C:17]([NH:19][C@H:20]([C:28]([NH:30][C@@H:31]([C:42]([NH:44][C@H:45]([C:50]([NH:52][C@H:53]([C:58]([NH2:60])=[O:59])[CH2:54][CH2:55][S:56][CH3:57])=[O:51])[CH2:46][CH:47]([CH3:48])[CH3:49])=[O:43])[CH2:32][C:33]1[C:41]2[C:36](=[CH:37][CH:38]=[CH:39][CH:40]=2)[NH:35][CH:34]=1)=[O:29])[CH2:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1)=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4]