HRID243626

反应详情

EQUATION

反应方程式

HRID 243626 的结构方程式

PROCEDURE

实验过程

Compound 21 was prepared using the methodology described for the preparation of compound 18, by substituting compound 14 with compound 20. Yield (0.276 g, 79.8%). 1H NMR (300 MHz, CDCl3) δ 7.21 (1H, t, J=7.7 Hz), 7.07 (1H, d, J=8.2 Hz), 6.99 (2H, s), 6.69 (1H, d, J=7.8 Hz), 2.49 (2H, t, J=7.3 Hz), 2.40 (2H, t, J=7.1 Hz), 1.78 (2H, brs), 1.69 (2H, t, J=6.7 Hz), 1.50-1.35 (4H, m). 13C NMR (75 MHz, CDCl3) δ 179.6, 172.2, 160.8, 149.7, 147.1, 135.0, 130.2, 117.3, 115.6, 113.5, 108.1, 36.7, 34.4, 29.1, 28.9, 25.5, 24.9.

WORKUP

后处理

  1. customYield (0.276 g, 79.8%)