Potassium Hydroxide → 5-[5-(6-Phenylhexyl)-thien-2-yl]-valeric acid
Reaction equation
O=[C:2]([C:14]1[S:18][C:17]([CH2:19][CH2:20][CH2:21][CH2:22][C:23]([O:25]C)=[O:24])=[CH:16][CH:15]=1)[CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1.[OH-].[K+].O.NN>C(O)COCCOCCO>[C:8]1([CH2:7][CH2:6][CH2:5][CH2:4][CH2:3][CH2:2][C:14]2[S:18][C:17]([CH2:19][CH2:20][CH2:21][CH2:22][C:23]([OH:25])=[O:24])=[CH:16][CH:15]=2)[CH:9]=[CH:10][CH:11]=[CH:12][CH:13]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
This compound is prepared analogously to Example 1b from: 22.8 g of methyl 5-[5-(1-oxo-6-phenylhexyl)-thien-2-yl]-valerate, 11.1 g of potassium hydroxide, 250 ml of triethylene glycol and 7.0 g of hydrazine hydrate.
Sources & evidence
- ORD record
- ord-524e09ec8289429e99ff8f73f14b535c
- Source dataset
- uspto-grants-1987_11
- Patent number
- US04705802
Reaction notes
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