4-Fluorobenzoic Acid → 4-Fluorobenzoic Acid
Reaction equation
[F:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][CH:3]=1>C1(OC2C=CC=CC=2)C=CC=CC=1.O=O>[F:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([O:8][C:4]2[CH:5]=[CH:9][CH:10]=[C:2]([F:1])[CH:3]=2)=[O:7])=[CH:4][CH:3]=1.[F:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][CH:3]=1Participants
5
Reactant 1
Product 2
Reagents, catalysts & solvents 2
Conditions
- Temperature
- 240 °C
Procedure
A 25-ml 2-necked Kjeldahl flask fitted with an air-cooling line and an oxygen introducing line was charged with 2.1 g of p-fluorobenzoic acid, 1.99 g of cupric oxide, and 2 ml of diphenyl ether as solvent, after which it was heated at 240° C. over an oil bath while blowing in oxygen at a rate of 30 ml per minute for 90 minutes. After cooling, the experiment was carried out as in Example 1 to recover 0.121 g of p-fluorobenzoic acid from the filtration residue. And from the filtrate there were obtained 0.656 g of m-fluorophenyl p-flurobenzoate and 1.000 g of p-fluorobenzoic acid by column chromatography. The yield of m-fluorophenyl p-fluorobenzoate was 37.4%, and the selectivity was 80.3%.
Workup
- customA 25-ml 2-necked Kjeldahl flask fitted with an air-cooling line
- temperatureAfter cooling
- filtrationto recover 0.121 g of p-fluorobenzoic acid from the filtration residue
Sources & evidence
- ORD record
- ord-5838d2e0747b4e2891ee5d6cf7a37a72
- Source dataset
- uspto-grants-1987_11
- Patent number
- US04705884
Reaction notes
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