Lithium borohydride → (3-Benzyloxy-4-iodophenyl)methanol
Reaction equation
[BH4-].[Li+].[CH2:3]([O:10][C:11]1[CH:12]=[C:13]([CH:18]=[CH:19][C:20]=1[I:21])[C:14](OC)=[O:15])[C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1>C1COCC1.[Cl-].[NH4+]>[CH2:3]([O:10][C:11]1[CH:12]=[C:13]([CH2:14][OH:15])[CH:18]=[CH:19][C:20]=1[I:21])[C:4]1[CH:5]=[CH:6][CH:7]=[CH:8][CH:9]=1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Conditions
- Temperature
- 60 °C
Procedure
1.18 g (54 mmol, 3 eq) of lithium borohydride are added to a solution of 6.9 g crude (17.98 mmol, 1 eq) of methyl 3-benzyloxy-4-iodobenzoate in 30 ml of THF. The reaction mixture is heated at 60° C. for 12 hours and then hydrolyzed in saturated ammonium chloride solution NH4Cl and extracted with ethyl acetate. 6.5 g of (3-benzyloxy-4-iodophenyl)methanol are obtained in oil form and are used in the following reaction without further purification.
Workup
- extractionextracted with ethyl acetate
Sources & evidence
- ORD record
- ord-2a15595a5b37457e9be50890b3622ef7
- Source dataset
- uspto-grants-2011_01
- Patent number
- US07863332B2
Reaction notes
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