HRID251200

反应详情

EQUATION

反应方程式

HRID 251200 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

Using General Procedure A: Reaction of 2-[4-(5,6,7,8-tetrahydro-quinolin-8-ylamino)-butyl]-isoindole-1,3-dione, 2-(6-bromomethyl-pyridin-2-yl)-isoindole-1,3-dione (Goswami, S. et al. J. Am. Chem. Soc. 1989, 111, 3425-6), and DIPEA in CH3CN gave 2-{4-[[6-(1,3-dioxo-1,3-dihydro-isoindol-2-yl)-pyridin-2-ylmethyl]-(5,6,7,8-tetrahydro-quinolin-8-yl)-amino]-butyl}-isoindole-1,3-dione as a tan solid. Deprotection with hydrazine following General Procedure E gave the free base. Conversion to the HBr salt using General Procedure D gave COMPOUND 355 as a white solid. 1H NMR (D2O) δ 1.51-1.55 (m, 4H), 1.71-1.85 (m, 1H), 1.91-2.03 (m, 1H), 2.13-2.18 (m, 1H), 2.32-2.36 (m, 1H), 2.46-2.54 (m, 1H), 2.67-2.74 (m, 1H), 2.90-2.99 (m, 4H), 3.98 (s, 2H), 4.38 (dd, 1H, J=5.7, 10.8 Hz), 6.90-6.96 (m, 2H), 7.80-7.86 (m, 2H), 8.30 (br d, 1H, J=8.1 Hz), 8.58 (br d, 1H, J=5.7 Hz); 13C NMR (D2O) δ 20.00, 20.43, 25.14, 25.26, 27.63, 39.57, 51.24, 52.88, 59.64, 113.08, 113.21, 125.70, 139.29, 140.38, 145.05, 146.08, 147.71, 151.86, 154.94; ES-MS m/z 326 (M+H). Anal. Calcd. for C19H27N5.3.4HBr.1.8H2O: C, 36.05; H, 5.41; N, 11.06; Br, 42.92. Found: C, 35.93; H, 5.24; N, 10.91; Br, 43.14.