Hydrochloric Acid → HCID 59425830, compound

HRID 252555Notes

Reaction equation

HRID 252555 reaction equation
[N:1]([CH2:4][CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([C:13]2[N:14]([CH2:26][CH3:27])[C:15]3[C:20]([C:21]=2[C:22]#[N:23])=[CH:19][CH:18]=[C:17]([O:24][CH3:25])[CH:16]=3)=[CH:9][CH:8]=1)=[N+]=[N-].Cl>[Pd].CO>[NH2:1][CH2:4][CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([C:13]2[N:14]([CH2:26][CH3:27])[C:15]3[C:20]([C:21]=2[C:22]#[N:23])=[CH:19][CH:18]=[C:17]([O:24][CH3:25])[CH:16]=3)=[CH:9][CH:8]=1

Participants

5

Reactant 2

HCID 313Hydrochloric AcidHCID 59425665HCID 59425665, compound

Product 1

HCID 59425830HCID 59425830, compoundYield 78%

Reagents, catalysts & solvents 2

HCID 23938PalladiumCatalystHCID 887MethanolSolvent

Procedure

2-[4-(2-Azidoethoxy)phenyl]-1-ethyl-6-methoxy-1H-indole-3-carbonitrile (410 mg, 1.14 mmol), prepared as in step A, above, is suspended in a solution of MeOH (20 mL) and concentrated HCl (500 μL). Pd/C (150 mg, 10%) is added, and this mixture is hydrogenated at 30 p.s.i. for 1 h. This is filtered and the filtrate is concentrated. The filtrate residue is partitioned between EtOAc and 0.5N NaOH. The organic layer is dried and concentrated. Purification by silica gel chromatography (10-30%, MeOH/CH2Cl2) yields 2-[4-(2-aminoethoxy)phenyl]-1-ethyl-6-methoxy-1H-indole-3-carbonitrile (298 mg, 78%), compound 267, as a white solid.

Workup

  1. filtrationThis is filtered
  2. concentrationthe filtrate is concentrated
  3. customThe filtrate residue is partitioned between EtOAc and 0.5N NaOH
  4. customThe organic layer is dried
  5. concentrationconcentrated
  6. customPurification by silica gel chromatography (10-30%, MeOH/CH2Cl2)

Sources & evidence

ORD record
ord-2cd01be5d98640cfb25e757d5dcda4fc
Source dataset
uspto-grants-2011_01
Patent number
US07868037B2

Reaction notes

Loading…