Lithium Hydroxide → 2-Indancarboxylic Acid

HRID 260685Notes

Reaction equation

HRID 260685 reaction equation
[C:1]([C:6]1(C(OCC)=O)[CH2:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[CH2:7]1)([O:3]CC)=[O:2].[OH-].[Li+]>C(O)C>[C:1]([CH:6]1[CH2:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[CH2:7]1)([OH:3])=[O:2]

Participants

4

Procedure

Dissolve 2,2-dicarboethoxy-indan (5.67 g, 21.7 mmol) in ethanol (150 mL). Add 1N lithium hydroxide (50 mL) and stir overnight at room temperature Reflux for 1 hour and concentrate the solution in vacuo. Partition between ethyl acetate and 6N hydrochloric acid. Separate the organic phase and wash with brine. Dry (MgSO4) and evaporate the solvent in vacuo to give an off-white solid. Distill (120°-160° C. @0.2-0.5 mmHg) to give 2-carboxy-indan (2.5 g, 71%).

Workup

  1. temperatureReflux for 1 hour
  2. concentrationconcentrate the solution in vacuo
  3. customPartition between ethyl acetate and 6N hydrochloric acid
  4. customSeparate the organic phase
  5. washwash with brine
  6. dry with materialDry (MgSO4)
  7. customevaporate the solvent in vacuo
  8. customto give an off-white solid
  9. distillationDistill (120°-160° C. @0.2-0.5 mmHg)

Sources & evidence

ORD record
ord-11ef88babff6476eb5cc38353907f3bf
Source dataset
uspto-grants-1996_06
Patent number
US05529996

Reaction notes

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