Sodium Iodide → 4-(3-Iodopropoxy)benzoic acid, methyl ester

HRID 266086Notes

Reaction equation

HRID 266086 reaction equation
Cl[CH2:2][CH2:3][CH2:4][O:5][C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12][CH3:13])=[O:11])=[CH:8][CH:7]=1.[I-:16].[Na+]>CC(C)=O.C(OCC)C>[I:16][CH2:2][CH2:3][CH2:4][O:5][C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12][CH3:13])=[O:11])=[CH:8][CH:7]=1

Participants

5

Procedure

Dissolve 4-(3-chloropropoxy)benzoic acid, methyl ester (6.97 g, 30.5 mmol) in anhydrous acetone (100 mL) and add powdered sodium iodide (16.0 g, 107 mmol). Heat at reflux under an argon atmosphere for 38 hours. Dilute with ethyl ether (100 mL) and filter through Celite® filter aid. Wash the filtrate with water and brine, then dry (MgSO4). Evaporate the solvent in vacuo to give 4-(3-iodopropoxy)benzoic acid, methyl ester as a yellow oil.

Workup

  1. temperatureHeat
  2. temperatureat reflux under an argon atmosphere for 38 hours
  3. filtrationfilter through Celite®
  4. filtrationfilter aid
  5. washWash the filtrate with water and brine
  6. dry with materialdry (MgSO4)
  7. customEvaporate the solvent in vacuo

Sources & evidence

ORD record
ord-b9e6c80487c947b2ad0bf088d354bf9a
Source dataset
uspto-grants-1997_07
Patent number
US05650416

Reaction notes

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