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HRID266365

反应详情

EQUATION

反应方程式

HRID 266365 的结构方程式

REACTANTS

反应物

4
结构：CCN(CC)CC
HCID8471

Triethylamine

C6H15N

结构：C[n+]1ccccc1Cl.[I-]
HCID167069

2-Chloro-1-methylpyridinium iodide

C6H7ClIN

结构：CCCCCCC(NS(=O)(=O)c1ccc(Cl)cc1)C(=O)O
HCID19032932

未命名化合物

结构：CCOC(=O)Cc1ccc(N)cc1.Cl
HCID24192282

Ethyl (4-aminophenyl)acetate--hydrogen chloride (1/1)

C10H14ClNO2

PRODUCTS

生成物

1
结构：CCCCCCC(NS(=O)(=O)c1ccc(Cl)cc1)C(=O)Nc1ccc(CC(=O)OCC)cc1
HCID19032973

未命名化合物

收率 26.2%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：ClC(Cl)Cl
溶剂HCID6212

Chloroform

CHCl3

PROCEDURE

实验过程

The procedure described in Example 177 was repeated, except that (RS)-2-(4-chlorobenzenesulfonylamino)octanoic acid (1 g) and ethyl 4-aminophenylacetate hydrochloride (581 mg) were condensed in chloroform (30 ml) in the presence of triethylamine (1.66 ml) and 1-methyl-2-chloropyridinium iodide (918 mg) to obtain (RS)-2-(4-chlorobenzenesulfonylamino)-N-(4-(ethoxycarbonylmethyl)phenyl)octanamide (350 mg).