Iodoethane → 4-Propylsaccharin

Participants

Reaction Steps

Following a procedure similar to that described in Example 28A 10 g (0.051 mol) of 4-methylsaccharin was reacted with 86 ml (0.10 mol) of a 1.18M solution of s-butyl lithium in THF and the resulting solution treated with 4.5 ml (0.050 mol) of ethyl iodide to give 10.15 g (89%) of 4-propylsaccharin, which on reaction with 5.32 ml (0.056 mol) of chloromethyl phenyl sulfide in toluene in the presence of tetrabutylammonium bromide afforded a 65% yield of 2-phenyl-thiomethyl-4-propylsaccharin as an oil, 1.8 g (0.0052 mol) of which, on reaction with 1.25 ml (0.016 mol) of sulfuryl chloride in MDC afforded 0.94 g (66%) of 2-chloromethyl-4-propylsaccharin.

Provenance & Evidence