Iodoethane → 4-Propylsaccharin
Reaction equation
[CH3:1][C:2]1[CH:12]=[CH:11][CH:10]=[C:9]2[C:3]=1[C:4](=[O:13])[NH:5][S:6]2(=[O:8])=[O:7].[CH:14]([Li])(CC)[CH3:15].C(I)C>C1COCC1>[CH2:1]([C:2]1[CH:12]=[CH:11][CH:10]=[C:9]2[C:3]=1[C:4](=[O:13])[NH:5][S:6]2(=[O:8])=[O:7])[CH2:14][CH3:15]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Following a procedure similar to that described in Example 28A 10 g (0.051 mol) of 4-methylsaccharin was reacted with 86 ml (0.10 mol) of a 1.18M solution of s-butyl lithium in THF and the resulting solution treated with 4.5 ml (0.050 mol) of ethyl iodide to give 10.15 g (89%) of 4-propylsaccharin, which on reaction with 5.32 ml (0.056 mol) of chloromethyl phenyl sulfide in toluene in the presence of tetrabutylammonium bromide afforded a 65% yield of 2-phenyl-thiomethyl-4-propylsaccharin as an oil, 1.8 g (0.0052 mol) of which, on reaction with 1.25 ml (0.016 mol) of sulfuryl chloride in MDC afforded 0.94 g (66%) of 2-chloromethyl-4-propylsaccharin.
Sources & evidence
- ORD record
- ord-3e5f4b6f184741c2976a9346befb82d7
- Source dataset
- uspto-grants-1997_07
- Patent number
- US05650422
Reaction notes
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