Hydrochloric Acid → 2H-1,5-Benzodioxepin-3(4H)-one
Reaction equation
[O:1]=[C:2]1[CH2:8][O:7][C:6]2[CH:9]=[CH:10][CH:11]=[CH:12][C:5]=2[O:4][CH:3]1C(OC)=O.CO.Cl>O>[O:1]=[C:2]1[CH2:3][O:4][C:5]2[CH:12]=[CH:11][CH:10]=[CH:9][C:6]=2[O:7][CH2:8]1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
3-Oxo-4-carbomethoxy-3,4-dihydro-2H-1,5-benzodioxepin (110 g.) is added to a mixture of methanol (210 ml.), concentrated hydrochloric acid (50 ml.) and water (160 ml.) and the mixture then is refluxed for 18 hours. The product is extracted with ether, and the ether extract washed with four 50 ml. portions of sodium bicarbonate solution, then twice with 50 ml. portions of water. After drying the washed ether extract over magnesium sulfate and evaporation to remove the solvent there is obtained 3-oxo-3,4-dihydro-2H-1,5-benzodioxepin.
Workup
- temperaturethe mixture then is refluxed for 18 hours
- extractionThe product is extracted with ether
- extractionthe ether extract
- washwashed with four 50 ml
- dry with materialAfter drying the washed ether
- extractionextract over magnesium sulfate and evaporation
- customto remove the solvent there
Sources & evidence
- ORD record
- ord-44c56e48478045f3aa81d409068f6f02
- Source dataset
- uspto-grants-1976_03
- Patent number
- US03944560
Reaction notes
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