Hydrogen Bromide → 3-Methyl-4-[(2-aminoethyl)thiomethyl]isothiazole hydrobromide

HRID 26870Notes

Reaction equation

HRID 26870 reaction equation
O[CH2:2][C:3]1[C:4]([CH3:8])=[N:5][S:6][CH:7]=1.Cl.[NH2:10][CH2:11][CH2:12][SH:13].[BrH:14]>>[BrH:14].[CH3:8][C:4]1[C:3]([CH2:2][S:13][CH2:12][CH2:11][NH2:10])=[CH:7][S:6][N:5]=1

Participants

4

Procedure

Reacting 4-hydroxymethyl-3-methylisothiazole (3.0 g.) with cysteamine hydrochloride (2.8 g.) in 48% aqueous hydrobromic acid (50 ml.) by the procedure of Example 1 gives 3-methyl-4-[(2-aminoethyl)thiomethyl]isothiazole hydrobromide. The base is obtained by basifying with aqueous potassium carbonate, extracting with chloroform, drying the extracts over magnesium sulphate and concentrating. Reacting the amine (5.0 g.) with methyl isothiocyanate (1.94 g.) in ethanol (25 ml.) under reflux for 30 minutes and purifying the product on a column of alumina with benzene as eluant gives N-methyl-N'-[2-(3-methyl-4-isothiazolylmethylthio)ethyl]thiourea. (Found: C, 40.8; H, 5.9; N, 16.1; S, 36.4. C9H15N3S3 requires: C, 41.3; H, 5.8; N, 16.1; S, 36.8).

Sources & evidence

ORD record
ord-46961948b49a47cd9dc289eac0bbaa17
Source dataset
uspto-grants-1979_04
Patent number
US04151288

Reaction notes

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