Hydrochloric Acid → 3-(2',4'-Difluoro-4-biphenylyl)-2-butenoic acid
Reaction equation
[F:1][C:2]1[CH:7]=[C:6]([F:8])[CH:5]=[CH:4][C:3]=1[C:9]1[CH:14]=[CH:13][C:12]([C:15](O)([CH3:20])[CH2:16][C:17]([OH:19])=[O:18])=[CH:11][CH:10]=1.Cl>C(O)(=O)C>[F:1][C:2]1[CH:7]=[C:6]([F:8])[CH:5]=[CH:4][C:3]=1[C:9]1[CH:14]=[CH:13][C:12]([C:15]([CH3:20])=[CH:16][C:17]([OH:19])=[O:18])=[CH:11][CH:10]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
1 g. of 3-(2',4'-difluoro-4-biphenylyl)-3-hydroxybutyric acid is dissolved in 5 ml. of acetic acid. 1 ml. of concentrated hydrochloric acid is added and the mixture is allowed to stand for 2 hours at 20° and poured onto ice. After the customary work up, 3-(2',4'-difluoro-4-biphenylyl)-2-butenoic acid, m.p. 193-195°, is obtained.
Workup
- additionpoured onto ice
Sources & evidence
- ORD record
- ord-34cf583e09c244a5ad2473ff8ed3f4c8
- Source dataset
- uspto-grants-1979_04
- Patent number
- US04151302
Reaction notes
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