Fluorene → HCID 178506660, compound
Reaction equation
[CH:1]1[C:13]2[CH2:12][C:11]3[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=3)[C:5]=2[CH:4]=[CH:3][CH:2]=1.C([Li:18])CCC>CCOCC>[C:1]1([Li:18])[C:13]2[CH2:12][C:11]3[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=3)[C:5]=2[CH:4]=[CH:3][CH:2]=1Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Here 5 g (30 mmol) fluorene, dissolved in ether, was reacted for three hours with 18.8 ml of butyllithium (1.6M in hexane). The solvent was evaporated to yield yellow fluorenyl lithium. Then 11.4 g (45 mmol) of Ph2SiCl2, i.e. diphenyl dichloro silane, was dissolved in 200 ml of pentane and the solid fluorenyl lithium was added in one portion to the pentane solution. After stirring for one hour, the mixture was filtered, the precipitated LiCl was eluated with 50 ml of ether, and the solvent evaporated from the combined organic layers to yield a yellow powder characterized by GC/MS as FlSiPh2Cl, i.e. fluorenyl-diphenyl chlorosilane. Crystallization in pentane yields colorless crystals of the product, from which a H-NMR-spectra could be obtained.
Workup
- customThe solvent was evaporated
Sources & evidence
- ORD record
- ord-a813c5e2e68246699780d2a3c74e871e
- Source dataset
- uspto-grants-1995_02
- Patent number
- US05393911
Reaction notes
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