HRID293027

反应详情

EQUATION

反应方程式

HRID 293027 的结构方程式

REACTANTS

反应物

6

结构：O=C([O-])O

Bicarbonate Ion

CHO3-

结构：[Na+]

Sodium ion

Na+

结构：ClCCl

Dichloromethane

CH2Cl2

结构：CCN(CC)CC

Triethylamine

C6H15N

结构：CS(=O)(=O)Cl

Methanesulfonyl chloride

CH3ClO2S

结构：CC(C)(C)OC(=O)N1CCC(F)(CO)CC1

tert-Butyl 4-fluoro-4-(hydroxymethyl)piperidine-1-carboxylate

C11H20FNO3

PRODUCTS

生成物

1

结构：CC(C)(C)OC(=O)N1CCC(F)(COS(C)(=O)=O)CC1

tert-Butyl 4-fluoro-4-{[(methanesulfonyl)oxy]methyl}piperidine-1-carboxylate

C12H22FNO5S