HRID3028

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID64774

Pyridinium fluoride

C5H6FN

结构：CCCC[C@@H](C)C[C@@H](/C=C/[C@@H]1C(SCCCCCC(=O)OC)=C(OC(=O)C(C)C)C[C@H]1O[Si](C)(C)C(C)(C)C)O[Si](C)(C)C(C)(C)C

HCID22883798

未命名化合物

PRODUCTS

生成物

结构：CCCC[C@@H](C)C[C@H](O)/C=C/[C@@H]1C(SCCCCCC(=O)OC)=C(OC(=O)C(C)C)C[C@H]1O

HCID22883799

未命名化合物

收率 64%

PROCEDURE

实验过程

Using as the material and reagent a hydrogen fluoride-pyridine solution (0.6 ml) and methyl(11R,12S,13E,15S,17R)-9-isobutyryloxy-11,15-bis(tert-butyldimethylsiloxy)-17,20-dimethyl-7-thiaprosta-8,13-dienoate (466 mg), the same procedure as in Example 2 was performed to obtain methyl(11R,12S,13E,15S,17R)-9-isobutyryloxy-11,15-dihydroxy-17,20-dimethyl-7-thiaprosta-8,13-dienoate (192 mg, 64%).

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-e25048cd0b1a4d4a97c39af9be62f679
来源数据集: uspto-grants-1998_03
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05731452
来源说明: uspto-grants-1998_03

反应 SMILES

N1C=CC=CC=1.F.[CH3:8][O:9][C:10](=[O:54])[CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][S:16][C:17]1[C@@H:21](/[CH:22]=[CH:23]/[C@@H:24]([O:32][Si](C(C)(C)C)(C)C)[CH2:25][C@H:26]([CH3:31])[CH2:27][CH2:28][CH2:29][CH3:30])[C@H:20]([O:40][Si](C(C)(C)C)(C)C)[CH2:19][C:18]=1[O:48][C:49](=[O:53])[CH:50]([CH3:52])[CH3:51]>>[CH3:8][O:9][C:10](=[O:54])[CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][S:16][C:17]1[C@@H:21](/[CH:22]=[CH:23]/[C@@H:24]([OH:32])[CH2:25][C@H:26]([CH3:31])[CH2:27][CH2:28][CH2:29][CH3:30])[C@H:20]([OH:40])[CH2:19][C:18]=1[O:48][C:49](=[O:53])[CH:50]([CH3:52])[CH3:51]