huagongshe.com
HRID3029

反应详情

EQUATION

反应方程式

HRID 3029 的结构方程式

REACTANTS

反应物

2
结构：F.c1ccncc1
HCID64774

Pyridinium fluoride

C5H6FN

结构：CCCC[C@@H](C)C[C@@H](/C=C/[C@@H]1C(SCCCCCC(=O)OC)=C(OC(=O)C(C)(C)C)C[C@H]1O[Si](C)(C)C(C)(C)C)O[Si](C)(C)C(C)(C)C
HCID22883800

未命名化合物

PRODUCTS

生成物

1
结构：CCCC[C@@H](C)C[C@H](O)/C=C/[C@@H]1C(SCCCCCC(=O)OC)=C(OC(=O)C(C)(C)C)C[C@H]1O
HCID22883801

未命名化合物

收率 55%

PROCEDURE

实验过程

Using as the material and reagent a hydrogen fluoride-pyridine solution (0.7 ml) and methyl(11R,12S,13E,15S,17R)-9-pivaloyloxy-11,15-bis(tert-butyldimethylsiloxy)-17,20-dimethyl-7-thiaprosta-8,13-dienoate (564 mg), the same procedure was performed as in Example 2 was performed to obtain methyl(11R,13E,15S,17R)-9-pivaloyloxy-11,15-dihydroxy-17,20-dimethyl-7-thiaprosta-8,13-dienoate (211 mg, 55%).