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HRID3032

反应详情

EQUATION

反应方程式

HRID 3032 的结构方程式

REACTANTS

反应物

2
结构：F.c1ccncc1
HCID64774

Pyridinium fluoride

C5H6FN

结构：CCCCC[C@@H](/C=C/[C@@H]1C(SCCCCCC(=O)OC)=C(OC(=O)c2ccccc2)C[C@H]1O[Si](C)(C)C(C)(C)C)O[Si](C)(C)C(C)(C)C
HCID22883804

未命名化合物

PRODUCTS

生成物

1
结构：CCCCC[C@H](O)/C=C/[C@@H]1C(SCCCCCC(=O)OC)=C(OC(=O)c2ccccc2)C[C@H]1O
HCID22883805

未命名化合物

收率 88.3%

PROCEDURE

实验过程

Using as the material and reagent a hydrogen fluoride-pyridine solution (0.3 ml) and methyl(11R,12S,13E,15S)-9-benzoyloxy-11,15-bis(tert-butyldimethylsiloxy)-7-thiaprosta-8,13-dienoate (239 mg), the same procedure as in Example 2 was performed to obtain methyl(11R,13E,15S)-9-benzoyloxy-11,15-dihydroxy-7-thiaprosta-8,13-dienoate (144 mg, 86%).