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HRID3038

反应详情

EQUATION

反应方程式

HRID 3038 的结构方程式

REACTANTS

反应物

2
结构：F.c1ccncc1
HCID64774

Pyridinium fluoride

C5H6FN

结构：CCCCC[C@@H](/C=C/[C@@H]1C(SCCCCCC(N)=O)=C(OC(=O)CCC)C[C@H]1O[Si](C)(C)C(C)(C)C)O[Si](C)(C)C(C)(C)C
HCID22883778

未命名化合物

PRODUCTS

生成物

1
结构：CCCCC[C@H](O)/C=C/[C@@H]1C(SCCCCCC(N)=O)=C(OC(=O)CCC)C[C@H]1O
HCID22883781

未命名化合物

收率 91%

PROCEDURE

实验过程

Using as the material and reagent a hydrogen fluoride-pyridine solution (0.2 ml) and (11R,12S,13E,15S)-9-butyryloxy-11,15-bis(tert-butyldimethylsiloxy)-7-thiaprosta-8,13-dienamide (169 mg), the same procedure was followed as in Example 2 to obtain (11R,12S,13E,15S)-9-butyryloxy-11,15-dihydroxy-7-thiaprosta-8,13-dienamide (101 mg, 91%).