Aluminium lithium hydride → 3-(3-Chloro-4-methoxymethoxyphenyl)propanol

HRID 322337Notes

Reaction equation

HRID 322337 reaction equation
[Cl:1][C:2]1[CH:3]=[C:4]([CH2:12][CH2:13][C:14](OCC)=[O:15])[CH:5]=[CH:6][C:7]=1[O:8][CH2:9][O:10][CH3:11].[H-].[Al+3].[Li+].[H-].[H-].[H-]>>[Cl:1][C:2]1[CH:3]=[C:4]([CH2:12][CH2:13][CH2:14][OH:15])[CH:5]=[CH:6][C:7]=1[O:8][CH2:9][O:10][CH3:11]

Participants

3

Reactant 2

HCID 21226445Aluminium lithium hydrideHCID 22009674Ethyl 3-(3-chloro-4-methoxymethoxyphenyl)propionate

Product 1

HCID 220096143-(3-Chloro-4-methoxymethoxyphenyl)propanolYield 97%

Procedure

In substantially the same manner as in Reference Example 82, ethyl 3-(3-chloro-4-methoxymethoxyphenyl)propionate was subjected to reduction with lithium aluminum hydride to obtain 3-(3-chloro-4-methoxymethoxyphenyl)propanol as an oil. The yield was 97%.

Sources & evidence

ORD record
ord-7eb7a663804f46d8b3cc3fa07f3cfc0e
Source dataset
uspto-grants-2001_04
Patent number
US06211215B1

Reaction notes

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