Hydrochloric Acid → 9-Oxoprostanoic acid
Reaction equation
[O:1]=[C:2]1[CH2:17][CH2:16][C@H:15]([CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH2:23][CH2:24][CH3:25])[C@H:3]1[CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][C:10]([O:12]CC)=[O:11].[OH-].[K+].Cl>CO>[O:1]=[C:2]1[CH2:17][CH2:16][C@H:15]([CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH2:23][CH2:24][CH3:25])[C@H:3]1[CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][C:10]([OH:12])=[O:11]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A suspension of 300 mg. of ethyl 9-oxoprostanoate in 20 ml. of aqueous methanol (1:1) containing 300 mg. of potassium hydroxide is stirred at 50° C. for 1 hour and then at room temperature for 18 hours. The resulting solution is acidified with 1N hydrochloric acid, concentrated and extracted several times with diethyl ether. The combined ether extracts are washed with saturated sodium chloride solution, dried with anhydrous magnesium sulfate and taken to dryness to give 256 mg. (94%) of product as an oil; λmax 5.75, 5.85 μ; nmr 1H broad singlet δ 9.89 (carboxyl proton, exchangeable).
Workup
- additionA suspension of 300 mg
- concentrationconcentrated
- extractionextracted several times with diethyl ether
- washThe combined ether extracts are washed with saturated sodium chloride solution
- dry with materialdried with anhydrous magnesium sulfate
- customto give 256 mg
Sources & evidence
- ORD record
- ord-0f00f345f8634da3822c61d1e441d150
- Source dataset
- uspto-grants-1977_04
- Patent number
- US04018811
Reaction notes
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