Hydrochloric Acid → De(2,3-dihydroxy) Nadolol Hydrochloride

関与物質

反応手順

1-(tert.-butyl)-3-azetidinol and 5,6,7,8-tetrahydro-α-naphthol were reacted in the same manner as in Example 1 to form 1-(5,6,7,8-tetrahydro-α-naphthoxy)-3-(tert.-butylamino)-2-propanol. A hydrochloric acid gas was blown into the obtained propanol. As a result 1-(5,6,7,8-tetrahydro-1-naphthoxy)-3-(tert.-butylamino)-2-propanol hydrochloride having a melting point of 148°-150° C was obtained. The yield was 70%.

情報源と証拠