Hydrochloric Acid → De(2,3-dihydroxy) Nadolol Hydrochloride
Reaction equation
[ClH:1].[C:2]1([O:12][CH2:13][CH:14]([OH:21])[CH2:15][NH:16][C:17]([CH3:20])([CH3:19])[CH3:18])[C:11]2[CH2:10][CH2:9][CH2:8][CH2:7][C:6]=2[CH:5]=[CH:4][CH:3]=1>>[ClH:1].[C:2]1([O:12][CH2:13][CH:14]([OH:21])[CH2:15][NH:16][C:17]([CH3:19])([CH3:18])[CH3:20])[C:11]2[CH2:10][CH2:9][CH2:8][CH2:7][C:6]=2[CH:5]=[CH:4][CH:3]=1Participants
3
Procedure
1-(tert.-butyl)-3-azetidinol and 5,6,7,8-tetrahydro-α-naphthol were reacted in the same manner as in Example 1 to form 1-(5,6,7,8-tetrahydro-α-naphthoxy)-3-(tert.-butylamino)-2-propanol. A hydrochloric acid gas was blown into the obtained propanol. As a result 1-(5,6,7,8-tetrahydro-1-naphthoxy)-3-(tert.-butylamino)-2-propanol hydrochloride having a melting point of 148°-150° C was obtained. The yield was 70%.
Sources & evidence
- ORD record
- ord-10c95d2680d54b58844bf0bc6120143f
- Source dataset
- uspto-grants-1977_04
- Patent number
- US04018824
Reaction notes
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