Ethyl Acetate → Pentachlorophenol
Reaction equation
FC1(F)C(Cl)=C(Cl)C(F)(F)C(Cl)=C1Cl.FF.F[C:18]1(F)[C:23]([Cl:24])=[C:22]([Cl:25])[C:21]([Cl:27])(F)[C:20]([Cl:28])=[C:19]1[Cl:29].FC1C(Cl)(F)C(Cl)(F)C(Cl)=C(Cl)C=1Cl.CC(=O)[O:47]CC>>[Cl:24][C:23]1[C:18]([OH:47])=[C:19]([Cl:29])[C:20]([Cl:28])=[C:21]([Cl:27])[C:22]=1[Cl:25]Participants
6
Procedure
In run A two principal product fractions are obtained: (1) 60.3 g, bp 91°-97° /31 mm, mp 30°; (2) 18.6 g, semisolid residue. Fraction (1) was identified as 1,1,4,4-tetrafluorotetrachloro-2,5-cyclohexadiene by comparison of its IR and MS data with those of a known sample of the compound (Hasek et al., Jour. Am. Chem. Soc., vol. 82, p. 543, 1960) Fraction (2) was indicated by fluorine NMR, IR, VPC and EA analyses to be a mixture of isomeric 1,1,4-trifluoropentachloro-2,5-cyclohexadiene and 1,5,6-trifluoropentachloro-1,3-cyclohexadiene.
Workup
- customIn run A two principal product fractions are obtained
Sources & evidence
- ORD record
- ord-178a1e808dd449bf9658c0c98ccad2a8
- Source dataset
- uspto-grants-1977_04
- Patent number
- US04020112
Reaction notes
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