Thiophenol → Benzene, [(6-bromohexyl)thio]-
Reaction equation
[C:1]1([SH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C(=O)([O-])[O-].[K+].[K+].[Br:14][CH2:15][CH2:16][CH2:17][CH2:18][CH2:19][CH2:20]Br>>[C:1]1([S:7][CH2:20][CH2:19][CH2:18][CH2:17][CH2:16][CH2:15][Br:14])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1Participants
4
Procedure
Thiophenol (3 g), potassium carbonate (5.64 g) and 1,6-dibromohexane (6.64 g) were reacted and treated in the same manner as in Preparation Example 99 to give 7.4 g of 6-phenylthiohexyl bromide.
Workup
- additiontreated in the same manner as in Preparation Example 99
Sources & evidence
- ORD record
- ord-ca68285e59d34206979c93e1ffc965a1
- Source dataset
- uspto-grants-1999_01
- Patent number
- US05864039
Reaction notes
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