Iodoethane → 4-Ethoxy-3-fluorobenzaldehyde

HRID 351820Notes

Reaction equation

HRID 351820 reaction equation
[F:1][C:2]1[CH:3]=[C:4]([CH:7]=[CH:8][C:9]=1[OH:10])[CH:5]=[O:6].[CH2:11](I)[CH3:12]>>[CH2:11]([O:10][C:9]1[CH:8]=[CH:7][C:4]([CH:5]=[O:6])=[CH:3][C:2]=1[F:1])[CH3:12]

Participants

3

Reactant 2

HCID 6340IodoethaneHCID 5872503-Fluoro-4-hydroxybenzaldehyde

Product 1

HCID 227146604-Ethoxy-3-fluorobenzaldehyde

Procedure

Following a similar procedure to that described in reference example 3, but starting from 3-fluoro-4-hydroxybenzaldehyde instead of 4-hydroxybenzaldehyde and using ethyl iodide instead of 2-iodopropane, the title compound of the example was obtained as an oil (48% yield).

Sources & evidence

ORD record
ord-a0f4eaa8711044519e69cfbb5a5b6abb
Source dataset
uspto-grants-2004_06
Patent number
US06743816B2

Reaction notes

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