HRID367124

反应详情

EQUATION

反应方程式

HRID 367124 的结构方程式

PROCEDURE

实验过程

The reaction procedure of Example 11 was followed except that 939 mg (3.24 mmol) of 2-(4-chloroanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 26 mg of lithium hydride and 551 mg of propyl iodide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 669 mg of 2-[(4-chlorophenyl)imino]-2,3-dihydro-3-propyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one (62%, recrystallized from a mixture of ether and hexane) as a low polarity substance and 112 mg of 2-[N-(4-chlorophenyl)-N-propylamino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (10%, recrystallized from ether) as a high polarity substance.

WORKUP

后处理

  1. customThe reaction procedure of Example 11
  2. customThe resulting residue was then purified through silica gel column chromatography (eluant: chloroform)