Methyl iodide → HCID 23287712, compound

Participants

Reaction Steps

The reaction procedure of Example 11 was followed except that 646 mg of 2-(4-trifluoromethylanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 18 mg of lithium hydride and 0.13 ml of methyl iodide were used. As a result, 565 mg of 3-methyl-2-[(4-trifluoromethylphenyl)imino]-2,3-dihydro-4H-pyrido[3,2-e]-1,3-thiazin-4-one was obtained as a low polarity substance, and 25 mg of 2-[N-methyl-N-(4-trifluoromethylphenyl)amino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one was obtained as a high polarity substance.

Provenance & Evidence