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HRID371915

反应详情

EQUATION

反应方程式

HRID 371915 的结构方程式

REACTANTS

反应物

3
结构：O=c1[nH]cc(F)c(=O)[nH]1
HCID3385

5-Fluorouracil

C4H3FN2O2

结构：O=C(Br)c1ccccc1
HCID12056

Benzoyl bromide

C7H5BrO

结构：O=C(c1ccccc1)n1c(=O)[nH]cc(F)c1=O
HCID12690827

3-Benzoyl-5-fluoropyrimidine-2,4(1H,3H)-dione

C11H7FN2O3

PRODUCTS

生成物

1
结构：O=C(c1ccccc1)n1cc(F)c(=O)n(C(=O)c2ccccc2)c1=O
HCID12690829

1,3-Dibenzoyl-5-fluoropyrimidine-2,4(1H,3H)-dione

C18H11FN2O4

收率 11.7%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：c1ccncc1
溶剂HCID1049

Pyridine

C5H5N

PROCEDURE

实验过程

In the same manner as described in Example 1 but using 2.6 g (0.02 mole) of 5-fluorouracil, 10 ml of absolute pyridine and 7.4 g (0.04 mole) of benzoyl bromide, 1.6 g of 3-N-benzoyl-5-fluorouracil (yield, 34%) and 270 mg of 1,3-di-N-benzoyl-5-fluorouracil (yield, 4%) were obtained.