Methyl iodide → HCID 22114273, compound
Reaction equation
[Cl:1][C:2]1[CH:3]=[C:4]([CH:12]=[CH:13][C:14]=1[OH:15])[O:5][CH2:6][C:7]([O:9][CH2:10][CH3:11])=[O:8].[CH3:16]I.[OH-].[Na+]>CN(C=O)C.O>[Cl:1][C:2]1[CH:3]=[C:4]([CH:12]=[CH:13][C:14]=1[O:15][CH3:16])[O:5][CH2:6][C:7]([O:9][CH2:10][CH3:11])=[O:8]Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
Ethyl 4 hydroxyphenoxyacetate(l.5 g, 7.6 mmol) was reacted with SO2Cl2 (1.5 mL) to give ethyl 3-chloro-4-hydroxyphenoxyacetate (700 mg, ~80% pure) as a white powder. To a solution of ethyl 3-chloro-4-hydroxyphenoxyacetate (700 mg, 3.0 mmol) and MeI(0.280 mL, 4.5 mmol) in DMF(5 mL) at 0° C. was added 10M aq.NaOH(0.320 mL, 3.2 mmol). The mixture was stirred at r.t. for 12 h, then diluted with H2O and extracted with EtOAc to give ethyl 3-chloro-4 methoxyphenoxy-acetate (700 mg).
Workup
- extractionextracted with EtOAc
Sources & evidence
- ORD record
- ord-52abf207a5514aa6bfe4a9ddef338bff
- Source dataset
- uspto-grants-2000_02
- Patent number
- US06020343
Reaction notes
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