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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 380865Generated: November 4, 2026

Methyl 4-pentynoate → (Z)-5-[2,3-Dihydro-5-fluoro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-4-pentynoic acid methyl ester

https://huagongshe.com/reaction/380865

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl 4-pentynoateHCID 543061—
Reactant(3Z)-5-fluoro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylidene]-2,3-dihydro-1H-indol-2-oneHCID 18363902—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
CatalystHCID 178418397HCID 178418397—
SolventDimethylformamideHCID 6228—
SolventTriethylamineHCID 8471—
Product(Z)-5-[2,3-Dihydro-5-fluoro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-4-pentynoic acid methyl esterHCID 20667781—

Reaction Steps

Using Method C above, 4-pentynoic acid methyl ester (75.7 mg, 0.68 mmol) (see Example 8, supra) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene)]-2H-indol-2-one (100 mg, 0.26 mmol) (Starting Material 6, supra) using (Ph3P)4Pd (31.2 mg) and CuI (5.0 mg) as catalyst in DMF (4 mL) and Et3N (4 mL) as solvent at 80° C. for 7 h to yield (Z)-5-[2,3-Dihydro-5-fluoro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-4-pentynoic acid methyl ester. (Yield 86 mg, 90%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06303793B1
Source datasetuspto-grants-2001_10
ORD IDord-e4209f99051b4c1e8491de9b10a8cfcc
Source noteuspto-grants-2001_10