Methyl 4-pentynoate → (Z)-5-[2,3-Dihydro-5-fluoro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-4-pentynoic acid methyl ester
Reaction equation
[C:1]([O:7][CH3:8])(=[O:6])[CH2:2][CH2:3][C:4]#[CH:5].[F:9][C:10]1[C:11](I)=[C:12]2[C:16](=[CH:17][CH:18]=1)[NH:15][C:14](=[O:19])/[C:13]/2=[CH:20]\[C:21]1[NH:22][CH:23]=[CH:24][C:25]=1[O:26][CH3:27]>C1C=CC([P]([Pd]([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.[Cu]I.CN(C=O)C.CCN(CC)CC>[CH3:8][O:7][C:1](=[O:6])[CH2:2][CH2:3][C:4]#[C:5][C:11]1[C:10]([F:9])=[CH:18][CH:17]=[C:16]2[C:12]=1/[C:13](=[CH:20]/[C:21]1[NH:22][CH:23]=[CH:24][C:25]=1[O:26][CH3:27])/[C:14](=[O:19])[NH:15]2Participants
7
Reactant 2
Product 1
Reagents, catalysts & solvents 4
Procedure
Using Method C above, 4-pentynoic acid methyl ester (75.7 mg, 0.68 mmol) (see Example 8, supra) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene)]-2H-indol-2-one (100 mg, 0.26 mmol) (Starting Material 6, supra) using (Ph3P)4Pd (31.2 mg) and CuI (5.0 mg) as catalyst in DMF (4 mL) and Et3N (4 mL) as solvent at 80° C. for 7 h to yield (Z)-5-[2,3-Dihydro-5-fluoro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-4-pentynoic acid methyl ester. (Yield 86 mg, 90%).
Sources & evidence
- ORD record
- ord-e4209f99051b4c1e8491de9b10a8cfcc
- Source dataset
- uspto-grants-2001_10
- Patent number
- US06303793B1
Reaction notes
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