Triethyl phosphite → Methyl (diethoxyphosphoryl)methoxyacetate
Reaction equation
Cl[CH2:2][O:3][CH2:4][C:5]([O:7][CH3:8])=[O:6].[P:9]([O:16]CC)([O:13][CH2:14][CH3:15])[O:10][CH2:11][CH3:12]>>[CH2:11]([O:10][P:9]([CH2:2][O:3][CH2:4][C:5]([O:7][CH3:8])=[O:6])([O:13][CH2:14][CH3:15])=[O:16])[CH3:12]Participants
3
Conditions
- Temperature
- 150 °C
Procedure
26 g (186 mmol) of methyl chloromethoxyacetate and 32 mL (186 mmol) of triethyl phosphite are placed in a round-bottomed flask and heated at 150° C. for 3 hours. The reaction progress is monitored by NMR. The reaction medium is concentrated under vacuum. 45 g (100%) of methyl (diethoxyphosphoryl)methoxyacetate are obtained directly in the form of a colorless liquid.
Workup
- concentrationThe reaction medium is concentrated under vacuum
Sources & evidence
- ORD record
- ord-f763b70300064a05a1b402dc1807d717
- Source dataset
- uspto-grants-2013_02
- Patent number
- US08383652B2
Reaction notes
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