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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 401184Generated: October 26, 2026

1-Bromo-4-fluorobenzene → 1-(4-Fluorophenyl)-2-(3-methoxyphenyl)ethanone

https://huagongshe.com/reaction/401184

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1-Bromo-4-fluorobenzeneHCID 9993—
Reactant1-(1,1'-Biphenyl)-4-yl-2-phenylethan-1-oneHCID 74817—
ReactantN-Methoxy-2-(3-methoxyphenyl)-N-methylacetamideHCID 14918162—
Product1-(4-Fluorophenyl)-2-(3-methoxyphenyl)ethanoneHCID 4315996737%

Reaction Steps

Followed the procedure described in Synthesis of Intermediate 14 using N-methoxy-2-(3-methoxyphenyl)-N-methylacetamide and 1-bromo-4-fluorobenzene to give desired Intermediate 53 (260 mg, 37% yield).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08741915B2
Source datasetuspto-grants-2014_06
ORD IDord-27e1bf2c2c16494e81401891487997d7
Source noteuspto-grants-2014_06