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HRID401184

反应详情

EQUATION

反应方程式

HRID 401184 的结构方程式

REACTANTS

反应物

3
结构：Fc1ccc(Br)cc1
HCID9993

1-Bromo-4-fluorobenzene

C6H4BrF

结构：O=C(Cc1ccccc1)c1ccc(-c2ccccc2)cc1
HCID74817

1-(1,1'-Biphenyl)-4-yl-2-phenylethan-1-one

C20H16O

结构：COc1cccc(CC(=O)N(C)OC)c1
HCID14918162

N-Methoxy-2-(3-methoxyphenyl)-N-methylacetamide

C11H15NO3

PRODUCTS

生成物

1
结构：COc1cccc(CC(=O)c2ccc(F)cc2)c1
HCID43159967

未命名化合物

收率 37%

PROCEDURE

实验过程

Followed the procedure described in Synthesis of Intermediate 14 using N-methoxy-2-(3-methoxyphenyl)-N-methylacetamide and 1-bromo-4-fluorobenzene to give desired Intermediate 53 (260 mg, 37% yield).