Hydrochloric Acid → 2,4-Di-tert-butyl-5-nitrophenol
Reaction equation
COC(=O)[O:4][C:5]1[CH:10]=[C:9]([N+:11]([O-:13])=[O:12])[C:8]([C:14]([CH3:17])([CH3:16])[CH3:15])=[CH:7][C:6]=1[C:18]([CH3:21])([CH3:20])[CH3:19].COC(=O)OC1C([N+]([O-])=O)=CC(C(C)(C)C)=CC=1C(C)(C)C.[OH-].[K+].Cl>CO>[C:18]([C:6]1[CH:7]=[C:8]([C:14]([CH3:16])([CH3:15])[CH3:17])[C:9]([N+:11]([O-:13])=[O:12])=[CH:10][C:5]=1[OH:4])([CH3:19])([CH3:20])[CH3:21]Participants
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
The mixture of carbonic acid 2,4-di-tert-butyl-5-nitro-phenyl ester methyl ester and carbonic acid 2,4-di-tert-butyl-6-nitro-phenyl ester methyl ester (4.2 g, 12.9 mmol) was dissolved in MeOH (65 mL) and KOH (2.0 g, 36 mmol) was added. The mixture was stirred at room temperature for 2 h. The reaction mixture was then made acidic (pH 2-3) by adding conc. HCl and partitioned between water and diethyl ether. The ether layer was dried (MgSO4), concentrated and purified by column chromatography (0-5% ethyl acetate-hexanes) to provide 2,4-di-tert-butyl-5-nitro-phenol (1.31 g, 29% over 2 steps) and 2,4-di-tert-butyl-6-nitro-phenol. 2,4-Di-tert-butyl-5-nitro-phenol: 1H NMR (400 MHz, DMSO-d6) δ 10.14 (s, 1H, OH), 7.34 (s, 1H), 6.83 (s, 1H), 1.36 (s, 9H), 1.30 (s, 9H). 2,4-Di-tert-butyl-6-nitro-phenol: 1H NMR (400 MHz, CDCl3) δ 11.48 (s, 1H), 7.98 (d, J=2.5 Hz, 1H), 7.66 (d, J=2.4 Hz, 1H), 1.47 (s, 9H), 1.34 (s, 9H).
Workup
- custompartitioned between water and diethyl ether
- dry with materialThe ether layer was dried (MgSO4)
- concentrationconcentrated
- custompurified by column chromatography (0-5% ethyl acetate-hexanes)
Sources & evidence
- ORD record
- ord-46c4a2c998c347828ab62b900f347b9f
- Source dataset
- uspto-grants-2014_06
- Patent number
- US08741925B2
Reaction notes
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