Hydrochloric Acid → (S)-2-(6-(5-(3-(2-Chlorophenyl)ureido)pyridin-2-yl)-1-oxoisoindolin-2-yl)-3-methylbutanoic acid

Participants

Reaction Steps

The compound of example 393 (75 mg, 0.150 mmol) was taken in THF (3 mL) and MeOH (1 mL) and to this reaction mixture, 1 N LiOH (31.47 mg, 0.75 mmol) was added and stirred at room temperature for 2-3 h. After completion of the reaction, solvent was evaporated and the residue obtained was dissolved in water and acidified with 1 N HCl to obtain the title compound, which was filtered and dried.

Provenance & Evidence