Trifluoroacetic acid → HCID 70008156, compound
Reaction equation
Cl.C([O:9][C:10]1[CH:11]=[C:12]([C:16]2[CH:21]=[CH:20][C:19]([Cl:22])=[CH:18][C:17]=2[N:23]2[CH2:28][C@H:27]([CH2:29][CH2:30][S:31]([CH3:34])(=[O:33])=[O:32])[N:26]([CH2:35][C:36]3[N:40]([CH2:41][C:42]4[CH:47]=[CH:46][C:45]([C:48]#[N:49])=[C:44]([F:50])[CH:43]=4)[CH:39]=[N:38][CH:37]=3)[CH2:25][C:24]2=[O:51])[CH:13]=[CH:14][CH:15]=1)C1C=CC=CC=1.[F:52][C:53]([F:58])([F:57])[C:54]([OH:56])=[O:55].[H][H]>CO.CCOC(C)=O.[Pd]>[F:52][C:53]([F:58])([F:57])[C:54]([OH:56])=[O:55].[OH:9][C:10]1[CH:11]=[C:12]([C:16]2[CH:21]=[CH:20][C:19]([Cl:22])=[CH:18][C:17]=2[N:23]2[CH2:28][C@H:27]([CH2:29][CH2:30][S:31]([CH3:34])(=[O:32])=[O:33])[N:26]([CH2:35][C:36]3[N:40]([CH2:41][C:42]4[CH:47]=[CH:46][C:45]([C:48]#[N:49])=[C:44]([F:50])[CH:43]=4)[CH:39]=[N:38][CH:37]=3)[CH2:25][C:24]2=[O:51])[CH:13]=[CH:14][CH:15]=1Participants
6
Procedure
To a solution of the product from Step D (383 mg, 0.527 mmol) in 10 mL of 1:1 MeOH/EtOAc was added trifluoroacetic acid (0.10 mL) and 10% palladium on carbon (300 mg). The solution was stirred under a balloon atmosphere of hydrogen at room temperature. After 1.5 hours, the solution was filtered through celite, the filter pad was rinsed with 1:1 MeOH/THF, and the filtrate was concentrated in vacuo. The crude material containing the titled product was used in the next reaction without further purification.
Workup
- filtrationthe solution was filtered through celite
- washthe filter pad was rinsed with 1:1 MeOH/THF
- concentrationthe filtrate was concentrated in vacuo
- additionThe crude material containing the titled product
- customwas used in the next reaction without further purification
Sources & evidence
- ORD record
- ord-5dd28f55d8d0498c86b8643465e0baaf
- Source dataset
- uspto-grants-2003_05
- Patent number
- US06562823B1
Reaction notes
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