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HRID414041

反应详情

EQUATION

反应方程式

HRID 414041 的结构方程式

REACTANTS

反应物

2
结构：O=S(Cl)Cl
HCID24386

Thionyl chloride

Cl2OS

结构：CC(=O)Oc1cc(C(=O)O)cc(OC(C)=O)c1OC(C)=O
HCID95088

Benzoic acid, 3,4,5-tris(acetyloxy)-

C13H12O8

PRODUCTS

生成物

1
结构：CC(=O)Oc1cc(C(=O)Cl)cc(OC(C)=O)c1OC(C)=O
HCID155506

3,4,5-Triacetoxybenzoyl chloride

C13H11ClO7

收率 100.7%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：ClCCCl
溶剂HCID11

1,2-Dichloroethane

C2H4Cl2

PROCEDURE

实验过程

In 100 ml of 1,2-dichloroethane, 57 g (0.19M) of 3,4,5-triacetoxybenzoic acid and 34 g (0.29M) of thionyl chloride were reacted at 60° C. for 2 hours. The excess thionyl chloride and 1,2-dichloroethane were distilled off under reduced pressure. Thus, 61 g of the desired compound was obtained.

WORKUP

后处理

  1. distillationThe excess thionyl chloride and 1,2-dichloroethane were distilled off under reduced pressure